prepare 500 ml of a 1:5 solution using a 1:10 solution and a 1:4n solution. what quantities will be used of each stock solution to make the 1:5 solution?
500 ml of a 1:5 solution contains 500*(1/5)=100 ml. of the concentrate.
So if x is the volume of 1:4, then 500-x is the volume of 1:10.
Hence
x(1/4)+(500-x)(1/10)=500*(1/5)
Solve for x to get x=333.33 ml.
a chemist needs 130ml of a 75% solution but has only 67% and 80% solutions available. find how many milliliters of each that should be mixed to get the desired solution.
To prepare 500 ml of a 1:5 solution using a 1:10 solution and a 1:4n solution, we need to find out the quantities of each stock solution required.
Let's break down the problem step-by-step:
Step 1: Determine the quantity of the 1:10 solution needed.
In a 1:10 solution, the concentration ratio is 1 part solute to 10 parts solvent.
Since we want to prepare a 1:5 solution, we need double the concentration of the 1:10 solution. Therefore, we'll need 2 parts of the 1:10 solution.
So, the quantity of the 1:10 solution needed can be calculated as follows:
Quantity of 1:10 solution = (2/5) * 500 ml
= 200 ml
Step 2: Determine the quantity of the 1:4n solution needed.
In a 1:4n solution, the concentration ratio is 1 part solute to 4 parts solvent.
Since we want to prepare a 1:5 solution, we need a lower concentration than the 1:4n solution. Therefore, we'll need to dilute the 1:4n solution by adding some solvent.
By comparing the concentration ratios, we can deduce that we need to dilute the 1:4n solution by a factor of 4/5.
So, the quantity of the 1:4n solution needed can be calculated as follows:
Quantity of 1:4n solution = (4/5) * 500 ml
= 400 ml
To summarize, to prepare the 500 ml of a 1:5 solution, you will need:
- 200 ml of the 1:10 solution
- 400 ml of the 1:4n solution
Keep in mind that these calculations assume that the volumes of the stock solutions are additive and that no volume changes occur during the mixing process. It's always a good idea to double-check your calculations and perform a final confirmation before preparing the solution.