Thursday
December 25, 2014

Homework Help: Chemistry

Posted by Robert on Friday, August 3, 2012 at 11:56am.

Find the equilibrium moles for the following reaction with initially 0.051 mol for Ethyl acetate, 0.260 mol for water and 0.03045 mol of acetic acid at equilibrium.

I'm not sure how to get the ones at equilibrium for the left side or even how much you have to take away for the reaction.

CH3CH2COOCH3 + H2O ---> CH3CH2OH + CH3COOH

initial:
EthylAc: 0.051 mol
Water: 0.260 mol
EthylOH: --------
Acetic: --------

rxn:
EthylAc:
Water:
EthylOH:
Acetic:

eq:
EthylAc: ?
Water: ?
EthylOH: ?
Acetic: 0.03045 mol

Thank you

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