Sunday
April 20, 2014

Homework Help: Chemistry

Posted by Robert on Friday, August 3, 2012 at 11:56am.

Find the equilibrium moles for the following reaction with initially 0.051 mol for Ethyl acetate, 0.260 mol for water and 0.03045 mol of acetic acid at equilibrium.

I'm not sure how to get the ones at equilibrium for the left side or even how much you have to take away for the reaction.

CH3CH2COOCH3 + H2O ---> CH3CH2OH + CH3COOH

initial:
EthylAc: 0.051 mol
Water: 0.260 mol
EthylOH: --------
Acetic: --------

rxn:
EthylAc:
Water:
EthylOH:
Acetic:

eq:
EthylAc: ?
Water: ?
EthylOH: ?
Acetic: 0.03045 mol

Thank you

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - I am given the following reaction: 2NH3(g) -----> N2(g) + 3H2(g) ...
Chemistry - Consider the following equilibrium at 1000K: 2SO2 (g) + O2 (g) ...
chemistry - For the following reaction: 2NH3 ----> N2 + 3H3 6.42 moles of NH3...
chemistry - For the following reaction: 2NH3 ----> N2 + 3H3 6.42 moles of NH3...
Chemistry - A reaction mixture of 4.0 mL of 0.002 M SCN- and 5.0 mL of 0.002 M ...
Chemistry - A student ran the following reaction in the laboratory at 650 K: H2(...
Chemistry - A student ran the following reaction in the laboratory at 327 K: CH4...
chemistry - The following reaction has an equilibrium constant of 0.50 at a ...
chemistry - A reaction mixture is in a 5.4 L flask at 25 oC initially contains ...
Chemistry - Consider the following equilibrium process at 700C: 2H2 + S2 ↔...

Search
Members