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October 30, 2014

October 30, 2014

Posted by **Devi** on Friday, August 3, 2012 at 5:55am.

- Solid Mechanics -
**MathMate**, Friday, August 3, 2012 at 6:40amI'll give it a try.

We have 50kN on 5cm², or 0.0005 m².

So the axial stress

σ_{x}= 10^{5}kPa

=100 MPa

σ_{y}=0

So draw the Mohr's circle (in the σ/τ plane) with between (0,0) and (100,0) as a diameter.

The centre is at (50,0).

To find the stresses at θ=30°

draw a diameter passing through the centre at 2*30=60° with the axis.

The stresses in that plane is shown by the extremities of the diameter, namely

σ=50±50cos(60°), and

τ=±50sin(60°).

Maximum shear stress is at θ=45° where

σx=σy=50, and

τxy=50

Hope that helps.

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