Posted by **Lauren** on Thursday, August 2, 2012 at 8:37pm.

A series RCL circuit has a resonant frequency of 1500 Hz. When operating at a frequency other than 1500 Hz, the circuit has a capacitive reactance of 5.0 Ù and an inductive reactance of 30.0 Ù. What are the values of (a) L and (b) C?

I know I should be using these 2 equations:

Xc= 1/(2*pi*f*C)

Xl= 2*pi*f*L

Since each have 2*pi*f in them, with rearranging and substituting, you get:

C= L/(Xl*Xc)

However, with this it leaves the 2 unknowns, and I'm not sure what other equations I could use?

- Physics -
**Elena**, Friday, August 3, 2012 at 2:41am
f=1500 Hz, X(C)=5Ω, X(L)=30 Ω

X(C)= 1/ωC,…..(1)

X(L)=ωL, ……..(2)

Multiply (1) by (2):

X(C) •X(L)= ωL/ ωC =L/C.

C=L/X(C) •X(L) …..(3)

Resonant frequency is

f=1/2π√(LC) =>

C=1/4•π²•f²•L ….(4)

Equate (3) and (4)

L/X(C) •X(L) =1/4•π²•f²•L,

L=sqrt{X(C) •X(L}/2•π•f=

=sqrt(5•30)/2π•1500=1.3•10^-3 H=

=1.3 mH,

C= L/X(C) •X(L)=

=1.3•10^-3/5•30=8.67•10^-6 =F=

= 8.67 μF

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