Posted by Robert on Thursday, August 2, 2012 at 6:01pm.
I'm confused for several reasons. First, I don't remember the entire problem so I don't remember the molarities. Second, in the last part of this post you have "we know that we have 1 M of each" and I don't think that is right. Third, you have in this post "0.015 mol*40 g/mol = 0.6 mol". That should be 0.6 gram. If I remember you had a density of HCl solution and the mass of that solution was mass = volume x density = 5 mL x density in g/mL = ? g. You can estimate the mass H2O by (mass soln - mass HCl) in the soln.
Yes I see my mistake now, because they first ask to find the moles of NaOH used, so would it simply be 0.015 mol?
If I remember you had a density of HCl solution and the mass of that solution was mass = volume x density = 5 mL x density in g/mL = ? g. You can estimate the mass H2O by (mass soln - mass HCl) in the soln.
The problem is that I don't have the solutions total mass.
Would it actually be from the 0.015 above * 40g/mol = 0.6g. - 0.5475g (HCl)?
I found your question of last Tuesday, July 31. You wanted mass HCl soln. That is 1.05 x 5.00 mL = 5.25 g
mass HCl in the 5.00 mL. That = mols HCl (which you obtained from M x L) x molar mass HCl = grams HCl. Then mass H2O = 5.25 - grams HCl = mass H2O.
Awesome, it's all clear now, thanks a lot again!
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