A can of paint and a paint brush cost a total of $35. If the can of paint costs $30 more than the paint brush, how much does the paint brush cost?
35 - 30 = ?
let the brush cost b dollars
then the paint costs b+30 dollars
together, they cost 35 dollars:
b + b+30 = 35
2b = 5
b = 2.50
brush: $2.50
paint: $32.50
Thanks, Steve. You're right.
I was wrong.
To solve this problem, let's assign variables to the unknown values. Let's say the cost of the paint brush is x dollars.
Since the can of paint costs $30 more than the paint brush, we can express the cost of the can of paint as x + $30.
According to the given information, the total cost of the paint can and the paint brush is $35. This can be written as the equation:
x + (x + $30) = $35
To solve for x, we can simplify the equation:
2x + $30 = $35
Next, let's isolate the x-term by subtracting $30 from both sides of the equation:
2x = $35 - $30
2x = $5
Finally, solve for x by dividing both sides of the equation by 2:
x = $5 / 2
x = $2.50
Therefore, the paint brush costs $2.50.