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September 1, 2014

September 1, 2014

Posted by **Ronny** on Thursday, August 2, 2012 at 2:34pm.

I have done this problem many times but I cannot find max profit. I keep fining a max income. I am lost and don't know what to do please help!

- Calculus Max Profit -
**MathMate**, Friday, August 3, 2012 at 10:51am"Assume the number sold is a linear function of the price"

but no information is given on the price elasticity, so we will assume, in general, an increase in price of $1 will increase sales by m units.

Under normal supply-demand curve, m is necessarily negative, of the order of -200 or so.

With that in mind, and knowing that (500,1.50) is a point on the line sales versus price, we construct the sales(y)-price(x) relation as:

(y-500)=m(x-1.50)

therefore, at a price of x, we expect sales of

y=m(x-1.5)+500

Total revenue,

R=xy

Total profit

P=xy - cost

=xy - (0.25x+100)

=x(m(x-1.5)+500) - (0.25x+100)

To get the maximum profit, we differentiate profit with respect to price, and equate to zero to find the optimum price:

dp/dx = m*x+m*(x-1.5)+1999/4 =0

Solve for x:

x=(6*m-1999)/(8*m)

If the price elasticity m=-100,

x=2599/800=$3.25

if m=-200

x=3199/1600=$2

if m=-300

x=3799/2400=$1.58

...

etc.

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