Posted by **Nancy** on Thursday, August 2, 2012 at 1:18pm.

Find the number of disintegrations per minute emitted by 1.1 mol of 232-Th in 1 min. The half-life of 232-Th is 1.4 x 1010 year

I was able to do this with the following technique:

1.1 x 6.022 x10^23 =6.62x10^23

1.4x10^10=7.358x10^15 minutes

I think then it is 6.62x10^23 x 7.358x10^15

But I want to learn how to do this problem using the formulas below instead of the .693/half life.

There are the following formulas:

starting amount) x (1/2)number of half-lives = ending amount (sometimes remaining rather than ending is used)

(1/2)number of half-lives is the decimal fraction which remains (1.000 is the original starting amount, 0.500 at the end of one half-life, 0.250 at the end of two, 0.125 at the end of three, etc.)

number of half-lives that have occurred can be expressed as (total time elasped ÷ length of half-life)

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