Posted by Shay on Thursday, August 2, 2012 at 11:32am.
6x = 21y + 15 for some y.
or,
2x = 7y + 5
since 2x is even, y must be odd.
y x
1 6
3 13
5 20
7 27
. . .
any number x of the form 2x = 7(2k+1)+5 is a solution, since
2x = 14k+7+5 = 14k+12
6x = 42k + 36
and 36 = 15 mod 21
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