algebra
posted by math on .
The perimeter of a rectangle garden is 80m oits length is 4m more than 5 times its width, find the dimensions of the garden

2W + 2L = 80
L = 5W + 4
Solve for length L and width W.
Using substitution,
2W + 2(5W +4) = 80
12 W = 72
W = 6
L = 34