what net force is required to bring a 1500kg car to rest from a speed of 100kph within a distance of acceleration.
Duplicate post; same answer.
To find the net force required to bring a car to rest from a given speed within a certain distance, we need to use the equations of motion.
First, we need to convert the speed from kilometers per hour (kph) to meters per second (m/s) as the SI unit for velocity is m/s.
To convert from kph to m/s, we divide the speed by 3.6:
Speed in m/s = 100 kph ÷ 3.6 ≈ 27.78 m/s
Next, we need to determine the acceleration. We can use the following equation of motion:
(vf^2 - vi^2) = 2as
Where:
vf = final velocity (0 m/s, as the car comes to rest)
vi = initial velocity (27.78 m/s)
a = acceleration
s = distance
Rearranging this equation to solve for acceleration (a):
a = (vf^2 - vi^2) / (2s)
Substituting the values:
a = (0^2 - 27.78^2) / (2s)
Now, we can solve for the acceleration. However, you did not provide the distance of acceleration. Please provide the distance, and I will be able to calculate the acceleration and subsequently find the net force required.