Posted by **Shaakira** on Wednesday, August 1, 2012 at 10:03pm.

Find the least positive integer that leaves the remainder 3 when divided by 7, remainder 4 when divided by 9, and remainder 8 when divided by 11. Using the Chinese Remainder Theorem.

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**MathMate**, Wednesday, August 1, 2012 at 10:11pm
See solution to the same problem at:

http://www.jiskha.com/display.cgi?id=1343870416

- Math -
**Anonymous**, Tuesday, November 4, 2014 at 9:39pm
I'm thinking of a number.

When I divide it by 2, the remainder is 1.

When I divide it by 3, the remainder is 2.

When I divide it by 4, the remainder is 3.

When I divide it by 5, the remainder is 4.

When I divide it by 6, the remainder is 5.

When I divide it by 7, the remainder is 6.

When I divide it by 8, the remainder is 7.

When I divide it by 9, the remainder is 8.

When I divide it by 10, the remainder is 9.

What is the smallest number with such a property?

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