Posted by **Kameesha** on Wednesday, August 1, 2012 at 12:27pm.

1. Which of the following best describes how the graph of f can be obtained from the graph of y = 1/x^2? f(x) = 4/x^2

a. vertical stretch by a factor of -4

b. horizontal shift of 4 units to the right

c. reflection over the y-axis, vertical shrink by a factor of 4

d. reflection over the x-axis, vertical stretch by a factor of 4

2. Determine the quadratic function f whose vertex is (3, -2) and passes through (2,1).

I have to type the answer in the form of f(x) = ax^2 + bx + c.

I would gladly appreciate the help.

- College Algebra -
**Steve**, Wednesday, August 1, 2012 at 1:11pm
1. you must have a typo. If f(x) = -4/x^2, then (d). Otherwise, none of the above. (a) would also be technically correct, but we don't usually denote stretching by negative values.

2. You know that

y = a(x-3)^2 - 2

so, plug in your point:

1 = a(2-3)^2 - 2

a = 3

so, y = 3(x-3)^2 - 2

= 3(x^2 - 6x + 9) - 2

= 3x^2 - 18x + 25

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