Posted by sanjeev kumar on Wednesday, August 1, 2012 at 3:34am.
Wi= 1200 rev/min = 20 rev/sec
= 20*2*pi rad/sec
Wf = 0; alpha= -1.5 rad/s^2
Wf = Wi + alpha*t
0 = 40*pi - 1.5*t
t = 40*pi/1.5 = 84 sec
Now,
theta = Wi*t + (1/2)*alpha*t^2
Plug in the values in this eqn. to get theta - the rotation of the wheel (in radians)before it comes to halt. Divide the result by 2*pi to convert into no. of revolutions.
Please help me to elaborate the answer as i tried but couldn't
Related Questions
Dynamics - A flywheel has an angular speed of 1200 rev/min when its motor is ...
Dynamics - A pelton wheel attains its operating speed of 800 rev/min within 2s ...
Physics - A flywheel with a diameter of 2.45 m is rotating at an angular speed ...
Dynamics - A pelton wheel attains its operating speed of 800 rev/min% determine ...
college physics - The flywheel of a steam engine runs with a constant angular ...
physics - The flywheel of a steam engine runs with a constant angular velocity ...
physics - The flywheel of a steam engine runs with a constant angular speed of ...
PHYSICS!!! - The flywheel of a steam engine runs with a constant angular ...
Physics - The flywheel of a steam engine runs with a constant angular speed of ...
physics - The flywheel of a steam engine runs with a constant angular speed of ...
For Further Reading