Wednesday

August 20, 2014

August 20, 2014

Posted by **John** on Wednesday, August 1, 2012 at 1:38am.

(a) What is the velocity of the motorist relative to the police car?

The magnitude and its direction

(b) What is the velocity of the police car relative to the motorist?

The magnitude and its direction

(c) If they are originally 250 m apart, in what time interval will the police car overtake the motorist?

A full working would be appreciated! thanks!

- Physics -
**Henry**, Wednesday, August 1, 2012 at 6:41pma. Vm = 77.2 - 94.5 = -17.3 km/h.

b. Vp=94.5 - 77.2=17.3 km/h=Velocity of policeman.

c. Vm*t=X km=Dist traveled bymotorist.

Eq1: 77.2t = X.

Vp*t = (X+250)=Dist. traveled by police.

Eq2: 94.5t = X+0.250)km.

In Eq2, substitute 77.2t for x:

94.5t = 77.2t + 0.2525

94.5t - 77.2t = 0.25

17.3t = 0.25

t = 0.01453 h. = 0.87 min = 52.3 s.

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