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November 29, 2014

November 29, 2014

Posted by **Ryan** on Tuesday, July 31, 2012 at 11:57pm.

- math -
**Steve**, Wednesday, August 1, 2012 at 10:42amI assume that by "at this spot" you mean 1.4km from the shore at the base of the lighthouse.

So, draw a diagram.

Let T be the top of the lighthouse

Let B be the base of the lighthouse

Let S be the point on the shore 60 form B

Let V be the location of the vessel (or ship, but S was taken)

Let O be the obstacle

We want to figure OV = BV - BO

SO = 1.4km = 1400m

tan 3.24° = TB/BV = 270/BV, so BV = 4769

SV = BV-BS = 4769-60 = 4709

The ship is 4709-60 = 4649m from shore, and thus 4649-1400m or 3249m or 3.25km from the obstacle

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