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If xΩy is defined as the smallest integer of which both x and y are factors, then 10Ω32 is how much greater than 6Ω20?

  • Math -

    xΩy = LCM(x,y)
    10Ω32 = LCM(10,32)=160
    6Ω20=LCM(6,20)=60
    can you take it from here?

  • Math -

    Yes! Thanks!

  • Math :) -

    You're welcome!

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