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July 31, 2014

July 31, 2014

Posted by **Jennfier** on Tuesday, July 31, 2012 at 8:22pm.

Find the area of the two regions created.

Find the perimeter of the two regions created.

- Circle question -
**Reiny**, Tuesday, July 31, 2012 at 10:13pmI drew the 12 cm chord at the end of a radius, giving me an isosceles triangle with sides 20,20 and 12

Define the "two regions" created.

- Circle question -
**Steve**, Wednesday, August 1, 2012 at 10:26amHmmm. Isn't every chord drawn at the end of a radius?

Any chord divides the circle into two regions.

The area of the segment is the area of the sector less the area of the triangle, or r^2/2 (θ - sinθ)

sin θ/2 = 6/20, so θ/2 = .3047

sinθ = .5723

The area of the segment is thus 200*(.6094-.5723) = 7.42

So, the rest of the circle has area 400π - 7.42 = 1249.2171

arc length subtended by chord: rθ = 20*.6094 = 12.188

other arc is 2πr - rθ = 40π - 12.188 = 113.476

so, the perimeters are arc length + chord length = 24.188 and 125.476

(assuming no stupid arithmetic errors)

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