Posted by Robertq on Tuesday, July 31, 2012 at 11:42am.
So I was thinking that when we use the NaOH, because of the stoichiometry of it's reaction with HCl, would the mass used of NaOH be the same for HCl, when it reaches equilibrium, well the neutral pH? Or am I completely off
So I was thinking that when we use the NaOH, because of the stoichiometry of it's reaction with HCl, would the mass used of NaOH be the same for HCl, when it reaches equilibrium, well the neutral pH? Or am I completely off
Those are two different questions.
mass HCl in 5.00 mL = mols HCl in 5.00 mL x molar mass HCl
mass 5.00 mL soln = 5.00 x 1.05 g/mL = ?
Because of the stoichiometry of the titration of NaOH + HCl, the MOLES are equal at the equivalence point but not the grams. 1mol HCl = 1 mol NaOH or 36.5 g HCl and 40 g NaOH. So mols are equal but not grams.
Amazing, thank you DrBob!
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