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April 18, 2014

April 18, 2014

Posted by **dee** on Tuesday, July 31, 2012 at 2:51am.

- math -
**Bosnian**, Tuesday, July 31, 2012 at 3:24am4 x + 3 y = 0

16 x + 3 = 8y

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Multiply the first equation by 4

16 x + 12 y = 0

16 x + 3 = 8y

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Subtract 8 y by second equation

16 x + 12 y = 0

16 x + 3 - 8 y = 8y - 8y = 0

______________

16 x + 12 y = 0

16 x + 3 - 8 y = 0

______________

Subtract 3 by second equation

16 x + 12 y = 0

16 x + 3 - 8 y - 3 = 0 - 3

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16 x + 12 y = 0

16 x - 8 y = - 3

________________

Subtract fsecond equation from first equation

16 x - 1 6 x + 12 y - ( - 8 y ) = 0 - ( - 3 )

12 y + 8 y = 3

20 y = 3 Divide both sides by 20

y = 3 / 20

Put y = 3 / 20 in first equation.

4 x + 3 y = 0

4 x + 3 * 3 / 20 = 0

4 x + 9 / 20 = 0 Subtract 9 / 20 by both sides

4 x + 9 / 20 - 9 / 20 = 0 - 9 / 20

4 x = - 9 / 20 Divide both sides by 4

x = - 9 / ( 20 * 4 )

x = - 9 / 80

Solution :

x = - 9 / 80 , y = 3 / 20

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