Saturday
March 25, 2017

Post a New Question

Posted by on .

A flywheel has an angular speed of 1200 rev/min when its motor is turned off. The wheel attains constant decelerations of 1.5 rad/s2 due to friction in its bearing. Determine the time required for the wheel to come to rest and the number of revolutions the wheel makes before it comes to rest

  • Dynamics - ,

    2π•f(fin)= 2π•f(init)-εt
    f(fin)=0, f(init) = 1200 rev/min =20 rev/s.
    2π•f(init)=εt
    t=2π•f(init)/ ε= 2π•20/1.5=83.8 s.

    2π•N= 2π•f(init) •t - εt²/2.
    N= f(init) •t - εt²/4π=
    =20•83.8 – 1.5•(83.8)²/4•π =
    = 838 rev.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question