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September 30, 2014

September 30, 2014

Posted by **Rajan** on Monday, July 30, 2012 at 1:49pm.

- Dynamics -
**Elena**, Monday, July 30, 2012 at 4:35pm1. The upward decelerated motion

v=vₒ-gt

At the top v=0

t=vₒ/g = 15/9.8=1.53 s.

h=vₒt-gt²/2.

h= vₒ²/2g=11.5 m.

2. Free fall from the height H+h = 30+11.5 = 41.5 m.

H=gt²/2 =>

t=sqrt(2•H/g) = sqrt(2•41.5/9.8)= 2.91 s.

v=gt =9.8•2.91=28.5 m/s.

Total time =1.53+2.91= 4.44 s.

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