a train starts from rest ad at the end of 90° seconds has a speed of 10km/h. What is the acceleration?
v=at
a=v/t
To find the acceleration of the train, we can use the following formula:
Acceleration (a) = (Final Velocity (v) - Initial Velocity (u)) / Time (t)
Given:
Initial Velocity (u) = 0 km/h (train starts from rest)
Final Velocity (v) = 10 km/h
Time (t) = 90 seconds
First, let's convert the velocities to m/s to maintain consistent units:
Initial Velocity (u) = 0 km/h = 0 m/s
Final Velocity (v) = 10 km/h = 10 * (1000/3600) = 2.778 m/s
Now we can calculate the acceleration:
Acceleration (a) = (2.778 m/s - 0 m/s) / 90 seconds
Simplifying the equation:
Acceleration (a) = 2.778 m/s / 90 seconds
Finally, we can calculate the acceleration:
Acceleration (a) = 0.0309 m/s² (rounded to four decimal places)
Therefore, the acceleration of the train is approximately 0.0309 m/s².
To find the acceleration of the train, we can use the formula:
acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity of the train is 0 km/h (starting from rest), the final velocity is 10 km/h, and the time taken is 90 seconds.
Let's calculate the acceleration:
acceleration = (10 km/h - 0 km/h) / 90 s
First, we need to convert the velocities from km/h to m/s since the unit of time we are using is seconds.
1 km/h = 1000 m/3600 s ≈ 0.278 m/s
Using this conversion, we can rewrite the acceleration formula as:
acceleration = ((10 km/h) * (0.278 m/s) - (0 km/h)) / 90 s
Simplifying this further gives:
acceleration = (2.78 m/s - 0 m/s) / 90 s
Finally, we calculate the acceleration:
acceleration ≈ 0.031 m/s^2
Therefore, the acceleration of the train is approximately 0.031 m/s^2.