Drysol contains 6g of aluminum chloride hexahydrate in 42ml of an alcohol base. What is the final strength of Drysol?____

What units? g/mL.

6/0.42 = 14+ g/mL

To calculate the final strength of Drysol, we need to determine the concentration of aluminum chloride hexahydrate in the solution. The concentration is typically expressed in terms of percent or molarity.

To find the concentration, we first need to calculate the amount of aluminum chloride hexahydrate in the solution. Given that Drysol contains 6g of aluminum chloride hexahydrate, we can proceed with the following steps:

1. Convert the volume of the alcohol base from milliliters (ml) to liters (L).
42 ml = 42/1000 = 0.042 L

2. Calculate the molarity (M) of aluminum chloride hexahydrate using the formula:
Molarity (M) = moles of solute / volume of solution in liters (L)

Since we have the mass of the solute (aluminum chloride hexahydrate), we can convert it to moles using its molar mass. The molar mass of aluminum chloride hexahydrate is:
(AlCl3 · 6H2O) = 133.34 g/mol

Moles of solute = Mass of solute / Molar mass
= 6 g / 133.34 g/mol
≈ 0.045 moles

Therefore, the molarity of the solution is:
Molarity (M) = 0.045 moles / 0.042 L
≈ 1.077 M

Thus, the final strength of Drysol is approximately 1.077 M, assuming the alcohol base does not affect the concentration significantly.