Posted by **Jessica** on Sunday, July 29, 2012 at 11:44pm.

Drivers pay an average of (mean $690) per year for automobile insurance the distribution of insurance payments is approximately normal with a standard deviation of 110 dollars. What proportion of drivers pay more than 100 dollars per year for insurance?

- statistics -
**catherine**, Monday, July 30, 2012 at 3:00pm
how to get answer to geometric mean problem? data: 25.4, 9, 16, 4.25, 8.11, 19?

- statistics -
**MathMate**, Monday, July 30, 2012 at 5:13pm
Check for typo in your post. If there are no typos, here's how you would proceed.

Standardize:

P(X>100)

=1-P(X≤100)

=1-P(Z≤(100-690)/110)

=1-P(Z≤-5.36)

Look up a probability table for

P(Z≤-5.36) and calculate the answer accordingly.

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