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March 26, 2017

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Drivers pay an average of (mean $690) per year for automobile insurance the distribution of insurance payments is approximately normal with a standard deviation of 110 dollars. What proportion of drivers pay more than 100 dollars per year for insurance?

  • statistics - ,

    how to get answer to geometric mean problem? data: 25.4, 9, 16, 4.25, 8.11, 19?

  • statistics - ,

    Check for typo in your post. If there are no typos, here's how you would proceed.

    Standardize:
    P(X>100)
    =1-P(X≤100)
    =1-P(Z≤(100-690)/110)
    =1-P(Z≤-5.36)
    Look up a probability table for
    P(Z≤-5.36) and calculate the answer accordingly.

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