Posted by **jimmy** on Sunday, July 29, 2012 at 11:31pm.

Assume that women's heights are normally distributed with a mean=63.6 in. and standard deviation = 2.5 in.

a) To be eligible for the US Marine Corps, a woman must have a height between 58 in. and 73 in. Find the percentage of women who satisfy that requirement.

b)If the requirement is changed to exclude the shortest 1% and exclude the tallest 1%, find the heights that are acceptable.

- statistics -
**MathGuru**, Monday, July 30, 2012 at 5:37pm
Use z-scores for both a) and b).

Formula:

z = (x - mean)/sd

a) Find both z-scores.

First z: x = 58, mean = 63.6, sd = 2.5

Second z: x = 73, mean = 63.6, sd = 2.5

Once you have both z-scores, check a z-table for the probability between the two scores. Convert to a percentage.

b) Find the two z-scores using a z-table for the shortest 1% and the tallest 1%. Once you have both z-scores, find x for both using the formula above, then go from there.

I hope this will help get you started.

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