Posted by **jimmy** on Sunday, July 29, 2012 at 11:31pm.

Assume that women's heights are normally distributed with a mean=63.6 in. and standard deviation = 2.5 in.

a) To be eligible for the US Marine Corps, a woman must have a height between 58 in. and 73 in. Find the percentage of women who satisfy that requirement.

b)If the requirement is changed to exclude the shortest 1% and exclude the tallest 1%, find the heights that are acceptable.

- statistics -
**MathGuru**, Monday, July 30, 2012 at 5:37pm
Use z-scores for both a) and b).

Formula:

z = (x - mean)/sd

a) Find both z-scores.

First z: x = 58, mean = 63.6, sd = 2.5

Second z: x = 73, mean = 63.6, sd = 2.5

Once you have both z-scores, check a z-table for the probability between the two scores. Convert to a percentage.

b) Find the two z-scores using a z-table for the shortest 1% and the tallest 1%. Once you have both z-scores, find x for both using the formula above, then go from there.

I hope this will help get you started.

## Answer This Question

## Related Questions

- hialeah campus - Assume that women's heights are normally distributed with a ...
- statistics - A survey found that women's heights are normally distributed with ...
- Statistics - Assume the heights of women are normally distributed with a mean ...
- Statustics - A survey found that women’s heights are normally distributed with ...
- statistics - Assume that women's heights are normally distributed with a mean ...
- statistics - The heights of American women aged 18 to 24 are normally ...
- statistics - The heights of American women aged 18 to 24 are normally ...
- Statistics Please help me :( - I have no idea where to even start. Suppose ...
- statistics - A survey found that women's heights are normally distributed with ...
- Statistics/Probability - Assume that women’s heights are normally distributed ...

More Related Questions