Post a New Question


posted by on .

A grinding wheel of radius 0.280 m rotating on a frictionless axle is brought to rest by applying a constant friction force tangential to its rim. The constant torque produced by this force is 75.3 N ยท m. Find the magnitude of the friction force.

  • physics - ,

    (friction force) * (radius) = torque

    Solve for the friction force, in Newtons.

    75.3/0.28 = ___ N

  • physic - ,

    Torque=r x friction
    so...solve for friction for

    torque is known:75.3 Nm
    radius is known:0.280m

    so Torque/radius=75.3Nm/0.280m
    meters cancel out =269N

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question