So I am suppose to evaulate this problem y=tan^4(2x) and I am confused.
my friend did this : 3 tan ^4 (2x) d sec^ 2x (2x)= 6 tan ^4 (2x) d sec^2 (2x)
She says it's right but what confuses me is she deriving the 4 and made it a three? I did the problem like this:
tan^4 (2x)= 4 tan^3 (2x) d sec ^2 (2x)(2x)= 8 tan^3 (2x) d sec^2 (2x)
Can anyone explain this to me?
calculus - Bosnian, Sunday, July 29, 2012 at 1:09am
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