An aqueous solution is made using 137g of diluted to a total solution volume of 1.30L .Calculate the molarity.molality and mass percent of solution.*assume a density of 1.08g/ml for the solution..

137 g of what?

mass % = (mass solute/100 g soln)*100
M = mols/L
m = mols/kg solvent.

To calculate the molarity, molality, and mass percent of the solution, we need to know the number of moles of solute (diluted ) and the mass of the solvent (aqueous solution). We can calculate the number of moles using the given mass and molar mass.

1. Calculate the number of moles of solute:
Molar mass of diluted = 137g/mol
Convert grams to moles using the formula:
moles = mass / molar mass
moles = 137g / 58.5 g/mol
moles = 2.344 moles

2. Calculate the mass of the solvent:
We are given the total solution volume (1.30 L) and the density of the solution (1.08 g/mL). We can use these values along with the formula density = mass / volume to find the mass of the solution.
mass of the solution = density Γ— volume
mass of the solution = 1.08 g/mL Γ— 1.30 L
mass of the solution = 1.404 g

3. Calculate the molarity:
Molarity is defined as the number of moles of solute per liter of solution.
molarity = moles / volume
molarity = 2.344 moles / 1.30 L
molarity = 1.803 M

4. Calculate the molality:
Molality is defined as the number of moles of solute per kilogram of solvent.
First, we need to convert the mass of the solvent from grams to kilograms.
mass of solvent = mass of solution - mass of solute
mass of solvent = 1.404 g - 137g
mass of solvent = 1.267 kg

molality = moles / mass of solvent (in kg)
molality = 2.344 moles / 1.267 kg
molality = 1.846 m

5. Calculate the mass percent of the solution:
Mass percent is the proportion of the solute's mass to the total mass of the solution, expressed as a percentage.
mass percent = (mass of solute / mass of solution) Γ— 100
mass percent = (137g / 1.404g) Γ— 100
mass percent = 9.75%

So, the molarity is 1.803 M, the molality is 1.846 m, and the mass percent is 9.75%.