Math ( i just need these two to finish my workshet
posted by Tony .
Show the solutions of
1. If a = 4, b = 3, and A = 36o.
2. If a = 3, b = 4, and A = 48.59o
Finding a "solution" means solving for all missing sides and angle measures in each triangle.)

Use Law of Sines.
1. sinB/b = sinA/a
sinB/3 = sin36/4
Multiply both sides by 3:
sinB = 3*sin36/4 = 0.44084
B = 26.16 Deg.
C = 180 36  26.16 = 117.8 Deg.
c/sinC = a/sinA
c/sin117.8 = 4/sin36
Multiply both sides by sin117.8:
c = 4*sin117.8/sin36 = 6.
2. Same procedure as #1.