Homework Help: chemistry

Posted by kellie on Saturday, July 28, 2012 at 11:34am.

Glutamate (Glu–) is the conjugate base form of glutamic acid (HGlu). The Ka of glutamic acid is 5.012 x 10^–5. You titrate 50 mL of 0.10 M sodium glutamate solution with 0.05 M HCl solution. Calculate the pH of the solution at the equivalence point.

Ive been trying to figure this out for hours! Please help me set this up!! thank you so much!!

chemistry - DrBob222, Saturday, July 28, 2012 at 2:10pm
You have 50 x 0.1 = 5 millimoles NaGlu which will require 100 mL of the 0.05M HCl. (HGlU) = 5 mmols/150 mL = 0.0333

.........HGlu ==> H^+ + Glu^-
I......0.0333.....0......0
C........-x........x......x
E......0.0333-x....x......x

Ka = (H^+)(Glu^-)/(HGlu)
Substitute from the ICE chart and solve for H^+, convert to pH.
........Glu^- + HOH ==> HGlu + OH^-
initial.

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