Known factors-weight 105 g---speed at start 60 mph---distance traveled 70 yds.
,what is the rate of decelleration?,
At what yard marker does it decellate to 35 mph
For each 5 feet higher from start - how much farther does it travel.
Thank you for your help,
Math/physics - Henry, Sunday, July 29, 2012 at 9:58pm
1h = 3600 s.
Vo=60mi/3600s * 1600m/mi = 26.7 m/s. = Initial velocity.
d = 70yd * 3Ft/yd * 1m/3.3Ft = 63.6 m =
V = 35mi/3600s * 1600m/mi = 15.6 m/s. =
1. a = (V^2-Vo^2)/2d
a = (243.4-711.1) / 127.2 = -3.68 m/s^2.
The neg. sign means deceleration.
2. Yard Marker = Yo + 70yds When traveling North or East.
Yard Marker = Yo - 70yds When traveling
South or West.
Yo = Yard marker at starting point.