Posted by Anonymous on Friday, July 27, 2012 at 5:47pm.
A fair, sixsided die is rolled eight times, to form an eightdigit number. What is the probability that the resulting number is a multiple of 8? Express your answer as a common fraction.

math  Reiny, Friday, July 27, 2012 at 9:56pm
Total number of numbers using 16
= 6^8 = 1679616
For any number to be divisible by 8, its last 3 digits must be divisible by 8
but these last two digits must contain only the digits from 1 to 6, with no zeros.
possible cases are:
112 136 144 152
216 224 232 256 264
312 336 344 352
416 424 432 456 464
512 536 544 552
616 624 632 656 664
Hoping that I didn't miss any, I count 27
so the front 5 numbers could be anything
there are 6^5 or 7776 different front numbers, each of those could have 27 different last three numbers
so there are 7776x27 or 209952 which are divisible by 8
prob that a number is a multiple of 8
= 209952/1679616
26244/209952
= 6561/52488
= 1/8
mmmmh, very interesting

math  yes, Monday, July 29, 2013 at 6:56am
That is right
Answer This Question
Related Questions
 counting and probability  A fair, sixsided die is rolled eight times, to form ...
 probability please help!!  A fair, sixsided die is rolled eight times, to form...
 probability  confused  A fair, sixsided die is rolled eight times, to form an...
 math  Hi! I'm Maddie. I need some help on my homework. Here are three problems ...
 Algebra 2/statistics  On a fair 6sided die, each number has an equal ...
 math  A sixsided die (with numbers 1 through 6) and an eightsided die (with ...
 math  If four standard sixsided dice are rolled,what is the probability that ...
 Math  Statistics  A sixsided die is rolled 36 times. What is the probability ...
 does anyone know probability????  The digits 2, 3, 4, 7, and 8 are each used ...
 probability  The digits 2, 3, 4, 7, and 8 are each used once in a random order ...
More Related Questions