Posted by Beth on .
Determine the activity of 1.11 g of 88Ra226 (a) in disintegrations per second (Bq) (b) and in Curies (Ci). The halflife is 1600 yr (1 yr = 3.156 x 10^7 s). 1 Ci is equal to 3.7 x 10^10 Bq.

chemistry 
DrBob222,
k = 0.693/t_{1/2}
Solve for k.
# atoms = N_{o} = (1.11/88)*6.02E23) = ?N_{o}. Then
R_{o} = kN_{o} = ? disintegrations per year. Convert to dps and Ci.