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July 28, 2014

July 28, 2014

Posted by **donovan** on Thursday, July 26, 2012 at 10:14pm.

- math -
**donovan**, Friday, July 27, 2012 at 4:54pmRichard is standing between two buildings in a town house development.The building on the left is 9 m away and the angle of elevation to its security spotlight A is 68 degrees. The building on the right is 6m away and the angle of elevation to its security spotlight B is 73 degrees which spotlight is farther away from ricchard and by how much ?

- math -
**Henry**, Friday, July 27, 2012 at 7:37pmWe draw 2 rt triangles:

X1 = 9 m. = Hor side.

Y1 = Ht. of light(L1) = Ver. side.

Ae = 68 Deg. = Angle of elevation.

Z1 = Hyp. = X1/cosAe = 9 / cos68=24 m.=

Dist. from Rich. to L1.

X2 = 6 m. = Hor. side.

Y2 = Ht. of L2 = Ver side.

Be = 73 Deg. = Angle of elevation.

Z2 = Hyp. = X2/cosBe = 6 / cos73=20.5 m

Z1 - Z2 = 24 - 20.5 = 3.5 m.

Therefore, the spotlight on the left is 3.5 m farther away.

y

- math -
**donovan**, Friday, July 27, 2012 at 10:50pmthanx

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