Posted by **ky** on Thursday, July 26, 2012 at 5:26pm.

On the Moon, a falling object falls just 2.65 feet in the first second after being dropped. Each second it falls 5.3 feet farther than in the previous second. How far would an object fall in the first ten seconds after being dropped?

- physics -
**drwls**, Thursday, July 26, 2012 at 6:06pm
You can either use a formula or construct a table. You should get the same answer.

If the falling object drops 2.65 feet the first second, the value of the accleration of gravity there is

g' = 5.3 ft/s^2.

In t = 10 seconds, use the formula

Y = (g'/2)*t^2, with

g' = 5.3 ft/s^2 and t = 10 s.

Y = 265 feet.

1st second: 2.65 ft

2nd second: 5.3 + 2.65 = 7.95 ft

3rd second: 7.95 + 5.3 = 13.25 ft

4th second: 18.55 ft

5th second: 23.85 ft

6th second: 29.15 ft

7th second: 34.45 ft

8th second: 39.75 ft

9th second: 45.05 ft

10th second: 50.35 ft

Total: 262.35 ft

## Answer This Question

## Related Questions

- arithmatics - On the Moon, a falling object falls just 2.65 feet in the first ...
- algebra - a body dropped from a height falls 16 feet during the first second, ...
- algebra - 5. 16t2 gives the distance in feet a free-falling object falls in t ...
- algebra - 5. 16t2 gives the distance in feet a free-falling object falls in t ...
- math - Below is the rule for calculating the velocity of a falling object. Use ...
- Physics - An object falls from rest. While falling it changes its speed by 10 ...
- math - Complete the following: (2 points per answer) Celestial Body Equatorial ...
- math - the distance, d, an object falls when dropped from a tower varies ...
- Applied Calculus - Suppose that an object is thrown down towards the ground from...
- math - An object that is falling or vertically projected into the air has it ...

More Related Questions