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November 28, 2014

November 28, 2014

Posted by **Anonymous** on Thursday, July 26, 2012 at 4:04pm.

- math -
**bobpursley**, Thursday, July 26, 2012 at 5:12pmFor the other two, the probablilty of two tails is 1/2*1/2=1/4

Therefore, pr(at least one head)=1-1/4=3/4

- math -
**Maddie**, Tuesday, August 20, 2013 at 5:22pmThere are a total of eight possible outcomes for three coins: HHH, HHT, HTH, THH, TTH, THT! HTT, TTT. Out of these eight outcomes, seven of these show at least one tail (all except HHH). After counting, we find that six of these seven outcomes have at least one head, so the probability is—6/7.

- math -
**hahaha**, Sunday, November 3, 2013 at 2:36pm6/7

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