How many moles of compound are in 26.5g of Na2CO3 x 10H2O?
To calculate the number of moles of a compound, you can use the formula:
Number of moles = mass (in grams) / molar mass
First, let's determine the molar mass of Na2CO3 x 10H2O.
The molar mass is calculated by summing up the atomic masses of all the elements in the compound.
The atomic masses are as follows:
- Sodium (Na) = 22.99 g/mol
- Carbon (C) = 12.01 g/mol
- Oxygen (O) = 16.00 g/mol
- Hydrogen (H) = 1.01 g/mol
Na2CO3 x 10H2O consists of 2 moles of sodium (Na), 1 mole of carbon (C), 3 moles of oxygen (O), and 20 moles of hydrogen (H).
So, the molar mass can be calculated as:
(2 * atomic mass of Na) + atomic mass of C + (3 * atomic mass of O) + (20 * atomic mass of H)
= (2 * 22.99 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol) + (20 * 1.01 g/mol)
= 46.00 g/mol + 12.01 g/mol + 48.00 g/mol + 20.20 g/mol
= 126.21 g/mol
Now, using the formula for calculating moles:
Number of moles = mass / molar mass
Number of moles = 26.5 g / 126.21 g/mol
Number of moles ≈ 0.210 moles
Therefore, there are approximately 0.210 moles of Na2CO3 x 10H2O in 26.5 grams of the compound.
To determine the number of moles of a compound, you need to use its molar mass. The molar mass is the mass of one mole of that substance.
To find the molar mass of Na2CO3 x 10H2O, you add up the atomic masses of all the atoms in the compound.
Let's first calculate the molar mass of Na2CO3:
- Sodium (Na) has an atomic mass of 22.99 g/mol.
- Carbon (C) has an atomic mass of 12.01 g/mol.
- Oxygen (O) has an atomic mass of 16.00 g/mol.
Na2CO3 consists of two sodium atoms, one carbon atom, and three oxygen atoms.
Molar mass of Na2CO3 = (2 * Na) + C + (3 * O) = (2 * 22.99 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol) = 105.99 g/mol
Now let's calculate the molar mass of 10H2O:
- Hydrogen (H) has an atomic mass of 1.01 g/mol.
- Oxygen (O) has an atomic mass of 16.00 g/mol.
10H2O consists of 20 hydrogen atoms and 10 oxygen atoms.
Molar mass of 10H2O = (20 * H) + (10 * O) = (20 * 1.01 g/mol) + (10 * 16.00 g/mol) = 202.20 g/mol
Finally, to find the molar mass of Na2CO3 x 10H2O, you add the molar masses of Na2CO3 and 10H2O:
Molar mass of Na2CO3 x 10H2O = Na2CO3 + 10H2O = 105.99 g/mol + 202.20 g/mol = 308.19 g/mol
Now you can calculate the number of moles of compound using the formula:
Number of moles = Mass of compound / Molar mass
Number of moles = 26.5 g / 308.19 g/mol ≈ 0.086 mol
Therefore, there are approximately 0.086 moles of Na2CO3 x 10H2O in 26.5g of the compound.