Posted by Anonymous on Thursday, July 26, 2012 at 9:31am.
SciMann
Best Answer - Chosen by Voters
Let UNITs guide you; always USE THEM in your calculation to prevent errors
moles of Na in samp = 0.78 g/ atwt Na = ??
x moles NaBr * MW NaBr + (moles Na - x moles NaBr) * MW NaCl = 2.01 g
x moles NaBr = [2.01 g - moles Na * MW NaCl] / [MW NaBr - MW NaCl] = ??
g NaBr = x moles NaBr * MW NaBr
wt fraction = g NaBr/2.01g = ?? (0.049 wt fraction of NaBr)
Plug and SOLVE
Or do you need more than this?
Related Questions
chem - a mixture of NaBr & NaCl has a mass of 2g & found to contain 0....
science - A mixture of {\rm NaCl} and {\rm NaBr} has a mass of 2.10{\rm g} and ...
chemistry - I used 10mL of unknown NaCl-NaBr mixture titrate with 0.10M silver ...
CHEMISTRY - I used 10mL of unknown NaCl-NaBr mixture titrate with 0.10M silver ...
chemistry - A student found that her mixture was 15% NH4Cl, 20% NaCl, and 75% ...
chemistry - formula: 2KClO3 + NaCL = 2KCl + NaCl + 3O2 MASS OF TEST TUBE & ...
Chemistry - A student found that her mixture was 15 percent NH4cl 20 percent ...
Chemistry - 0.7g of an unknown mixture of NaHCO3 and Na2CO3 is mixed with 3mL of...
Chem-Lab-HELP!! - Heating 1.124g of an unknown NaHCO3-NaCl mixture resulted ina ...
Chemistry - 25.0 mL of a NaCl solution (concentration unknown) was found to ...
For Further Reading