Posted by **Anonymous** on Wednesday, July 25, 2012 at 10:33pm.

can someone please explain why the answer to this is negative infinity? I keep getting positive.

lim

x--> - infinity x^3-2/x^2+x

- calculus -
**Bosnian**, Wednesday, July 25, 2012 at 10:56pm
Go on: wolframalpha dot com

When page be open in rectangle type:

limit x^3-2/x^2+x as x-> - infinity

and click option =

After few seconds when you see result click option:

Show steps

On wolfram alpha dot com you can practice any kind of calculus.

That is good just for practice.

You can't use wolframalpha on exam.

- calculus -
**Reiny**, Thursday, July 26, 2012 at 8:18am
Just get a feel for the numbers

x ---> - infinity

for very large negative numbers , x^3 - 2 becomes "

"hugely negative"

but x^2 + x becomes + "very large"

since -/+ = - , and the numerator is larger than the denominator by a factor of x,

the answer is -negative infinity

or

(x^3 - 2)/(x^2 + x) = x - 1 + (x+2)/(x^2+x)

lim (x^3-2)/(x^2+x) as x---> -∞

= lim (x-1) + lim (x+2)/(x^2+x) as x---> -∞

since intuitively we can see that lim (x+2)/(x^2+x) --> 0 as x ---> -∞

we are left with lim x-1 as x -->-∞

which is -∞

## Answer this Question

## Related Questions

- Calculus - Find the horizontal asymptote of f(x)=e^x - x lim x->infinity (e^x...
- Calc. Limits - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/0...
- calc - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/0= +/- ...
- Calc Please Help - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/...
- Math - 1. If -1/infinity = infinity or -infinity ? 2. If lim x->infinity^- = ...
- Math - 1. If -1/infinity = infinity or -infinity ? 2. If lim x->infinity^- = ...
- calculus - interval of convergence - infinity of the summation n=0: ((n+2)/(10^n...
- calculus - interval of convergence - infinity of the summation n=0: ((n+2)/(10^...
- Pre-cal - Please determine the following limits if they exist. If the limit does...
- Calculus - Does the series (1+sin(n))/(10^n) from summation 0 to positive ...

More Related Questions