Physics
posted by Zac on .
A block of mass m = 2.00 kg rests on the left edge of a block of mass M = 8.00 kg. The
coefficient of kinetic friction between the two blocks is 0.300, and the surface on which the 8.00
kg block rests is frictionless. A constant horizontal force of magnitude F = 10.0 N is applied to
the 2.00kg block, setting it in motion across the top of the lower block. If the distance across the
larger block is 3.00 m (from front edge of smaller block to rightmost edge of larger block),
(a) how long will it take the smaller block make it to the right side of the 8.00kg block. (b) How
far will the 8.00kg block move in this time?

m1=2 kg, m2=8 kg, μ=0.3, F=10 N.
For m1:
m1•g=N,
m1•a1=FF(fr) = F μ•N=F μ•m1•g.
a1=F/m1  μ•g = 10/2 0.3•9.8 = 2.06 m/s²
For m2:
m2•a2=F(fr)
a2=F(fr)/m2= μ•m1•g/m2 = 0.3•2•9.8/8 = 0.735 m/s².
Distances
x1=a1•t²/2,
x2=a2•t²/2,
x1=x2+L,
a1•t²/2 = a2•t²/2 + L,
Solve for t
t=2.13 s.
x2=a2•t²/2= 1.67 m