Posted by Dan on .
The work done by an electric force in moving a charge from point A to point B is 3.75 x 10^3 J. The electric potential difference between the two points is VA  VB = 54.6 V. What is the charge?
Not sure if I did this correctly:
I believe this is an equation:
deltaV= (Wab)/q
So, 54.6 V= (3.75 X 10^3 J)/q
q= 6.868 X 10^5???
Also, would this be in microcoulombs or coulombs?

Physics 
drwls,
Your answer is in coulombs and is correct.