Wednesday
September 17, 2014

Homework Help: Physics

Posted by Dan on Wednesday, July 25, 2012 at 5:41pm.

The work done by an electric force in moving a charge from point A to point B is 3.75 x 10^-3 J. The electric potential difference between the two points is VA - VB = 54.6 V. What is the charge?

Not sure if I did this correctly:

I believe this is an equation:
deltaV= (-Wab)/q

So, 54.6 V= (-3.75 X 10^-3 J)/q
q= -6.868 X 10^-5???
Also, would this be in microcoulombs or coulombs?

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