The work done by an electric force in moving a charge from point A to point B is 3.75 x 10^-3 J. The electric potential difference between the two points is VA - VB = 54.6 V. What is the charge?
Not sure if I did this correctly:
I believe this is an equation:
deltaV= (-Wab)/q
So, 54.6 V= (-3.75 X 10^-3 J)/q
q= -6.868 X 10^-5???
Also, would this be in microcoulombs or coulombs?
Your answer is in coulombs and is correct.
To find the charge (q), we can rearrange the equation:
deltaV = (-Wab) / q
Given:
deltaV = 54.6 V
Wab = 3.75 x 10^-3 J
Plugging in these values, we have:
54.6 V = (-3.75 x 10^-3 J) / q
To isolate q, we can cross-multiply:
-q * 54.6 V = -3.75 x 10^-3 J
Now, divide both sides by -54.6 V to solve for q:
q = (-3.75 x 10^-3 J) / (-54.6 V)
Calculating this equation, we get:
q ≈ 6.868 x 10^-5 C
So, the charge is approximately 6.868 x 10^-5 Coulombs (C).
To find the charge, we can rearrange the equation deltaV = (-Wab)/q to solve for q.
Given:
deltaV = 54.6 V
Wab = 3.75 x 10^-3 J
We can substitute these values into the equation:
54.6 V = (-3.75 x 10^-3 J)/q
To solve for q, we can rearrange the equation:
q = (-3.75 x 10^-3 J) / (54.6 V)
Now we can calculate the value of q:
q = -6.868 x 10^-5 Coulombs
The charge is approximately -6.868 x 10^-5 Coulombs (C). The negative sign indicates that the charge is negative, implying that it is an electron. The value is in coulombs, not microcoulombs.