Posted by Sara on .
When the conductivity is at a minimum, what must be true about the amount of Ba(OH)2 compared to H2SO4?
The Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4-2.
Why does it not conduct at this low point?
Why does it conduct more before and after this minimum point
Can someone please help with this I am not that great at chemistry. Thankyou fo any help that I get
Ba(OH)2 is a strong electrolyte and conducts electrical current easily.
H2SO4 ionizes to H^+ and HSO4^- and conducts electricity easily. So why not when they are mixed in the right proportions. Because BaSO4 is formed, it is essentially insoluble, therefore, no ions so no conduction.
H2SO4 + Ba(OH)2 ==> BaSO4 + H2O
When the conductivity is at a minimum, that means that stoichiometric amounts of Ba(OH)2 and H2SO4 are present (neither in excess) and the only materials in the reaction vessel are H2O and BaSO4. BaSO4 is not very soluble and H2O doesn't ionize appreciably.
If the pH value was 3.6, what is the [H+]?