Posted by **Alyonka** on Wednesday, July 25, 2012 at 3:49pm.

The bicyclists were 300 miles apart at 3 p.m. and were headed toward each other. If they met at 9 p.m. and one was traveling 20 mph faster than the other, what was the speed of each bicyclist?

So far these are the equations I have gotten:

Distance1 + Distance2= 300miles

rate1(time1) + rate2(time2)= 300 miles

rate1= rate2 + 20 mph

time1 + time2 = 6 hrs

However I cant combine them into one equation...

How would you do that

- Algebra -
**Henry**, Thursday, July 26, 2012 at 9:24pm
X mi/h = Speed of #1.

(X+20) mi/h = Speed of #2.

d1 + d2 = 300 Miles.

6x + 6(x+20) = 300

6x + 6x+ 120 = 300

12x = 300 - 120 = 180

X = 15 mi/h.

X+20 = 15 + 20 = 35 mi/h.

- Algebra -
**Henry**, Thursday, July 26, 2012 at 9:28pm
NOTE: Each rider was on the road 6 hrs.

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