Friday

July 25, 2014

July 25, 2014

Posted by **Robert** on Wednesday, July 25, 2012 at 2:17pm.

- One very long wire carries current 10.0 A to the left along the x axis. A second very long wire carries current 75.0 A to the right along the line

(y = 0.280 m, z = 0).

(a) Where in the plane of the two wires is the total magnetic field equal to zero? (along the y axis)

(b) A particle with a charge of -2.00 µC is moving with a velocity of 150 Mm/s along the line (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle.

(c) What If? A uniform electric field is applied to allow this particle to pass through this region undeflected. Calculate the required vector electric field.

- Physics - Electromagnetism -
**Elena**, Wednesday, July 25, 2012 at 4:39pm(a)

Magnetic field of the long current carrying wire according to Biot-Savert Law is

B=μₒI/2•π•a

The desired point is separated by distance “x” from the 1st current and by distance (d+x) from the 2nd current (along y-axis).

μₒI1/2•π•x=μₒI2/2•π•(d+x),

10•(0.28+x)=75•x

2.8+10x=75 x.

65x=2.8

x=0.431 m.

(b) Magnetic force (Lorentz force) is

F=qvB sinα.

Since the motion of the particle is along the straight line, then F=0

(c) Electric field has to be applied along the direction of the particle motion (E↑↑ῡ, E↑↓ῡ)

- Physics - Electromagnetism -
**Robert**, Thursday, July 26, 2012 at 9:09amthank you Elena!

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