Physics
posted by ice on .
PLEASE ANSWER ASAP!!!!!!!!!! step by step
a) find the acceleration experienced by the driver of a car traveling at 50km/h if the car hits a pole and crumples 50cm.
b) repeat part a) for a car traveling 100km/h

a) Vo = 50 km/h = 13.89 m/s
T = "Crumpling time" = X/(Vo/2)
= 2*0.50 m/13.89 m/s = 0.072 s
(Vo/2 is the average speed of the car during crumpling)
Acceleration = Vo/T = Vo^2/(2X)
= 193 m/s^2
b) It is not reasonable to assume that the crumple distance will remain 50 cm at the higher speed. More information is needed. 
can you explain it a bit clearer

v=50 km/h =50000/3600=13.89 m/s
For accelerated motion
s=vₒt+at²/2 … (1)
v=vₒ+at………(2).
Final v=0 => t= vₒ/a.
Substitute “t” in (1)
a=  vₒ²/2•s=  (13.89)²/2•0.5=
=  195.9 m/s²