Posted by ice on Wednesday, July 25, 2012 at 6:06am.
a) Vo = 50 km/h = 13.89 m/s
T = "Crumpling time" = X/(Vo/2)
= 2*0.50 m/13.89 m/s = 0.072 s
(Vo/2 is the average speed of the car during crumpling)
Acceleration = Vo/T = Vo^2/(2X)
= 193 m/s^2
b) It is not reasonable to assume that the crumple distance will remain 50 cm at the higher speed. More information is needed.
can you explain it a bit clearer
v=50 km/h =50000/3600=13.89 m/s
For accelerated motion
s=vₒt+at²/2
(1)
v=vₒ+at
(2).
Final v=0 => t= -vₒ/a.
Substitute t in (1)
a= - vₒ²/2s= - (13.89)²/20.5=
= - 195.9 m/s²
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