Posted by **hanan** on Tuesday, July 24, 2012 at 11:13pm.

A sample of air contains 32.7 µg/m3

of beryllium dust. How many atoms of beryllium are

present in a room with dimensions of 8 feet by

13.6 feet by 15.6 feet?

Answer in units of atoms

- science -
**drwls**, Wednesday, July 25, 2012 at 8:17am
Compute the room volume in ft^3 and convert it to cubic meters.

8*13.6*15.6 = 1797 ft^3 = 50.9 m^3

With 32.7*10^-6 g per m^3, there are 1.66*10^-3 gram of Be dust in the room.

Convert that to moles using the atomic weight of Be (9.0 g/mol), and then use Avogadro's number for the number of atoms.

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