How many milliliters of 4.6 M HCl must be

transfered from a reagent bottle to provide
16 g HCl for a reaction?
Answer in units of mL

To find the number of milliliters (mL) of 4.6 M HCl needed, we can use the formula:

Volume (V) = Amount (n) / Concentration (C)

First, we need to determine the amount of HCl required for the reaction. The molar mass of HCl is 36.46 g/mol, so 16 g of HCl is equal to:

Amount (n) = Mass / Molar mass
Amount (n) = 16 g / 36.46 g/mol

Next, we can substitute the values into the formula to find the volume:

V = n / C
V = (16 g / 36.46 g/mol) / 4.6 mol/L

Now, we can proceed with the calculations:

V = (16 / 36.46) / 4.6
V ≈ 0.4378 L

Since 1 L is equal to 1000 mL, we can convert liters to milliliters by multiplying by 1000:

V = 0.4378 * 1000
V ≈ 437.8 mL

Therefore, approximately 437.8 mL of 4.6 M HCl should be transferred from the reagent bottle to provide 16 g HCl for the reaction.