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March 31, 2015

March 31, 2015

Posted by **Anonymous** on Tuesday, July 24, 2012 at 4:12pm.

- algebra** -
**MathMate**, Wednesday, July 25, 2012 at 12:05amA={1,3,5,7,9}

B={5,10}

A∩B={5}

Assuming random sampling,

P(B)=|B|/|S|=2/10=1/5

P(A)=|A|/|S|=5/10=1/2

P(A∩B)=1/10

Finally,

P(B|A)=P(B∩A)/P(A) (by definition)

I'll let you take it from here.

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