Posted by
**Anonymous** on
.

IMAGINE- a building 6400km. high. On the ground floor, a person weighs 175lbs when he steps on a spring scale how much would the man weigh on the same scale if he were standing at the top floor? HINT: Note that 6400km is also the radius of the earth so that the top floor is 2Re from the earths center. Think about what this means for Fgrav before you start plugging in numbers or making conversions

I KNOW THIS MUCH----- confuesed what to plug in where. and what not to plug in. The weight is equal ‘mg”

On the Earth surface acceleration due to gravity is

mg=GmM/R²,

g=G•M•/R²,

where

the gravitational constant G =6.67•10^-11 N•m²/kg²,

Earth’s mass is M = 5.97•10^24 kg,

Earth’s radius is R = 6.378•10^6 m.

g=9.8 m/s²

Let's find “g” at the height “h” . Distance between the mas “m” (the person) and the center of the Earth is 2R =>

m•g1= G•m•M/(2R)²

g1= G•M/4R²=g/4

In the "high" building mg1= mg/4

•answered below - Damon, Monday, July 23, 2012 at 7:32pm

if r = 2R then r^2 = 4 R^2

then weight = (1/4) original

•PHYSICS! okay so would it be

(6.67*10^-11)(5.97*10^24)(77.87)/4(6.378*10^6)^2?!?!?!